Aposrot + Bposrot = Cposrot / Solve for Bposrot (from Aposrot F.O,R) 5000Lprize!

[Beowulf Zessinthal]

 

.. its Sunday! .. rotational algebra anyone? 

I spent yesterday melting my brain with tests and 2D paper grids, and today i thought i would just try and buy the answer!

5000L to whoever first ims me the answer to this problem .. i will announce the winner here when its done Thanks for any efforts!

 

//Join 2 prims and add this to root prim


vector Apos= <0.142, 0.0, 0.471>;//Aposrot (to be Frame of Reference)
rotation Arot= <0.0, -0.195, 0.0, 0.981>;
vector Bpos= <0.4, 0.0, 0.1>;
rotation Brot= <0.0, -0.469, 0.0, 0.883>;
vector Cpos;
rotation Crot;
    
default
{
    state_entry(){
    llSetLinkPrimitiveParams(2, [PRIM_POS_LOCAL, Apos, PRIM_ROT_LOCAL, Arot]);
    llSetLinkPrimitiveParams(2, [PRIM_TEXT, "Aposrot.\n(now add 'unknown' Bposrot)",<1,1,1>, 1]);
    llSleep(4);

    //Aposrot + Bposrot (in Aposrot Frame of Reference)
    llSetLinkPrimitiveParams(2, [PRIM_POS_LOCAL, Apos+ Bpos*Arot, PRIM_ROT_LOCAL, Brot*Arot]);
    
    llSetLinkPrimitiveParams(2, [PRIM_TEXT, "Cposrot.",<1,1,1>, 1]); 
    Cpos= (vector) llList2String( llGetLinkPrimitiveParams(2, [PRIM_POS_LOCAL]) , 0);
    Crot= (rotation) llList2String( llGetLinkPrimitiveParams(2, [PRIM_ROT_LOCAL]) , 0);
    llOwnerSay("_________\nAposrot= "+(string)Apos + (string)Arot);
    llOwnerSay("Cposrot= "+(string)Cpos + (string)Crot);

    llSleep(4);
    llOwnerSay("Aposrot + Bposrot = Cposrot / Solve for Bposrot (also from Aposrot Frame of Reference)");
    llSleep(4);
    llOwnerSay("Answer should be ~:\nBposrot= <0.4, 0.0, 0.1><0.0, -0.469, 0.0, 0.883>");
    llSetLinkPrimitiveParams(2, [PRIM_POS_LOCAL, Apos, PRIM_ROT_LOCAL, Arot]);
    llSetLinkPrimitiveParams(2, [PRIM_TEXT, "Aposrot.\n(now add 'unknown' Bposrot)",<1,1,1>, 1]);
    
    }

}

 

 

[Rolig Loon]

That's fairly straightforward.

Brot = Crot/Arot

and

Bpos = (Cpos - Apos)/Arot

 

[Beowulf Zessinthal]

I sit grinning .. i had found  ..

Brot= (ZERO_ROTATION/Arot)*Crot;

a half hour ago .. and just now also managed to derive

// Apos + (Bpos*Arot) = Cpos
// Cpos -  Apos =  (Bpos*Arot)
so   (Cpos - Apos)/Arot = Bpos  (same as yours:)

but your Brot is simpler so you still win! ..   Sending prize now !