Simple question for float result

[SubZeroWins]

Hi all,

Im doing a simple math like 5/2 and the result it returns its 2.000000

default
{
    touch_start(integer total_number)
    {
    float Test=5/2;
    llSay(0,(string)Test);
    }
}

What am I doing wrong? 😵

[Profaitchikenz Haiku]

try 5.0 / 2.0

[SubZeroWins]

Thanks pal lol 😆

[Mollymews]

we can get a tiny performance gain when we replace float division by multiplication

5.0 * 0.50;  // 5.0 / 2.0

5.0 * 0.33; // 5.0 / 3.0

division is the most time expensive arithmetic operation on general hardware math processing units

[Profaitchikenz Haiku]

Yes, division is tricky, multiplication by the inverse is faster, but..... where do you get the inverse from other than by a division somewhere?

What was more interesting here is that the literals took precedence over the cast to a float. I'm sure many people would have expected that once they had said "I want a float" then the right-hand side of the expression would itself have been implicitly converted to floats.

I wouldn't have assumed so, but I'm old, and I learned programming in a very strange way on a mixture of Forth/Fortran on Honeywells and PDPs, and with those systems you always had to specify the numeric literals to be of the intended form.

 

 

[Nova Convair]

Never expect something in coding. You know it - or it will not work. 😁

5 is an integer - 2 is an integer -> the expression will use integer math then.

If at least one number is a float ( 5.0/2 ) then float math will be used.

The result goes to the left side of the equation and it will be converted to whatever is needed. But that doesnt affect the calculation.

I set everything manually, by using float or integer numbers or have variables of the correct type or by enforcing the type: (float)intvar

Since I have never seen a documentation of the compiler I can't trust it 😁

[Mollymews]

edit: what Nova said

 

 

 

Edited February 17, 2021 by Mollymews