LSL IF OR statement

[Jenna Huntsman]

Hey!

I'm having trouble getting a script to read the incoming number from link_message, and if it doesn't match either numbers, then return.

Here's the code I've got:

if(number != (10006 || 10008))
{
    llWhisper(0, "Wrong number!\n" + (string)number + "::" + message);
    return;
}

I've tried the statement as many different forms, such as:

• number == !(10006 || 10008)
• number != 10006 || 10008
• number != 10006 | 10008
• number != (10006 | 10008)
• number == !(10006 | 10008)

None of which seem to work properly.

How can I perform this check?

Edited May 25, 2020 by Jenna Huntsman

[Ruthven Ravenhurst]

3 minutes ago, Jenna Huntsman said:

if((number != 10006) || (number != 10008))

Also this should be an && test, as the OR will always result to true in this case, so:

if((number != 10006) && (number != 10008))

Edited May 25, 2020 by Ruthven Ravenhurst

[Jenna Huntsman]

3 minutes ago, Ruthven Ravenhurst said:

 

Thank you! Got it working, though had to modify your command a little - here's what I've got now:

if((number != 10006) && (number != 10008))

 

[Innula Zenovka]

I like to use llListFindList rather than a simple if...else comparison  for tests like this because it's so much easier to add and remove items to test for:

default
{
	state_entry()
	{

	}
	touch_start(integer total_number)
	{
		integer iNeedle = 3;
		list lHaystack =[
			1,2,3,4,5	
			];
		if(~llListFindList(lHaystack,[iNeedle])){
			llOwnerSay((string)iNeedle+" is an item in the list");
		}
		else{
			llOwnerSay((string)iNeedle+" is not an item in the list");
		}
	}
}

 

Edited May 25, 2020 by Innula Zenovka